Hi

finding the roots using the quadratic formula

3y^2– 2y + 12 = 0

 

 

 

    x = -.5 + 2isqrt(35)/6

    x = -.5 - 2isqrt(35)/6

Sum of the roots = -1

Product: .25 + 4*35/36 

Note i^2 = -1 

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