SOLUTION: What are the points at x=-4, x=0, and x=4 on the graph y=4sin(2x+(π/4))?

Question 406414: What are the points at x=-4, x=0, and x=4 on the graph y=4sin(2x+(π/4))?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What are the points at x=-4, x=0, and x=4 on the graph y=4sin(2x+(3.14/4))?
use functional notation
f(x)=4sin(2x+(3.14/4))
Make sure your calculator set to radians instead of degrees.
f(0)=4sin(0+(3.14/4))=2.828
f(-4)=4sin(-8+(3.14/4))=
=4sin(-7.215)=-3.21
f(4) =4sin(8+(3.14/4))
=4sin(8.785)=2.388
ans:
f(0)=2.828
f(-4)=-3.21
f(4)=2.388
see the graph below

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SOLUTION: What are the points at x=-4, x=0, and x=4 on the graph y=4sin(2x+(&#960;/4))?

SOLUTION: What are the points at x=-4, x=0, and x=4 on the graph y=4sin(2x+(π/4))?