SOLUTION: A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right. The distance from home plate to the pitcher�s mound is 60 feet 6 inch

Question 402911: A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right. The distance from home plate to the pitcher�s mound is 60 feet 6 inches. Find the distance from the pitcher�s mound to second base. (Hint: The pitcher�s mound is not exactly halfway between home plate and second base.)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A baseball diamond is laid out so that the bases are 90n feet apart and at right angles as shown at the right.
The distance from home plate to the pitcher�s mound is 60 feet 6 inches.
Find the distance from the pitcher�s mound to second base.
:
The distance from home plate to 2nd base is the hypotenuse (h)
h =
h =
h =
h = 127.279 which is 127 + .279(12) = 127 ft 3.35 inches
therefore:
127' 3.35" - 60' 6" = 66 ft 9.35 inches from pitchers mound to 2nd base
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