SOLUTION: Hello,
Please hep me to solve this problem: Find all exact value solutions [o,360) for sin^2x-2sinx-3 = 0
My work:
x^2-2x-3 = 0
sinx = 3
sinx = -1
sin^-1(3) = None
sin^-
Algebra.Com
Question 390905: Hello,
Please hep me to solve this problem: Find all exact value solutions [o,360) for sin^2x-2sinx-3 = 0
My work:
x^2-2x-3 = 0
sinx = 3
sinx = -1
sin^-1(3) = None
sin^-1(-1) = -90
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
sin^-1(-1) = -90 is actually correct, BUT -90 is not in [0, 360), so the desired solution is -90 + 360 = 270.
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