SOLUTION: (please show the steps to how the rest of the problems were solved)
Using exact values, find the value of:
A.12sin 30 degree - 6 tan 45 degree + sec 45 degrees/ 52
12·1/2 -6·
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Question 389693: (please show the steps to how the rest of the problems were solved)
Using exact values, find the value of:
A.12sin 30 degree - 6 tan 45 degree + sec 45 degrees/ 52
12·1/2 -6· 1 + √2/52 = √2/52
B.Sin2A + tan3A/2 - cos A + sec(a+ 15)
Sin2A + tan3A/2 - cos A + sec(a+ 15)= √3/2 + 1 - √3/2 + √2 = 1+√2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Using exact values, find the value of:
A.12sin 30 degree - 6 tan 45 degree + sec 45 degrees/ 52
12*1/2 - 6*1 + √2/52 = √2/52
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B. Sin2A + tan3A/2 - cos A + sec(a+ 15)
Is it tan(3A/2), or (tan(A/2))^3 ?
----------
Sin2A + tan3A/2 - cos A + sec(a+ 15)= √3/2 + 1 - √3/2 + √2 = 1+√2
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