SOLUTION: 5) Solve for all values of 2 sin θ + sqrt 3=0 when 0° ≤ θ ≤ 360°. a)240°, 300° b)150°, 210° c)60°, 120° d)60°, 300° Answer: a Can you please check to

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Question 388841: 5) Solve for all values of 2 sin θ + sqrt 3=0 when 0° ≤ θ ≤ 360°.
a)240°, 300° b)150°, 210° c)60°, 120° d)60°, 300°
Answer: a
Can you please check to see If did it right.
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!

 when 





We know that , not 

but that tells us that the reference angle of q is 60°.

We also know that the sine is a negative number in the third and fourth
quadrants.  To find the angle whose reference angle is 60° in the 3rd
quadrant we add 180° to the reference angle 60°, and get 240°.  To find the
angle whose reference angle is 60° in the 4th quadrant we subtract the
reference angle 60° from 360° and get 300°.   

So yes you're right.

Edwin
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