SOLUTION: Solve the following trigonometric equations over the interval 0≤θ≤2π:
4tan(θ/2)-4=0
Algebra.Com
Question 379975:  Solve the following trigonometric equations over the interval 0≤θ≤2π:
4tan(θ/2)-4=0 
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
 Given 4tan(theta/2) - 4 = 0, we have tan(theta/2) = 1 --> theta/2 = pi/4, 5pi/4, 9pi/4, etc. This leaves us theta = pi/2, 5pi/2 (given the allowable range). 
RELATED QUESTIONS
Solve the equation for 0 ≤ θ ≤ 2π. 
cosθ - sinθ = 0  (answered by Fombitz)
Solve the following equations for 0 ≤ θ ≤ 180 degrees.
6.a. sin^2... (answered by Theo)
Use trigonometric identities to solve tan(2θ)+tan(θ)=0 exactly for... (answered by Alan3354)
Solve the equation (2 cos θ + 1)(tan θ − 1) = 0 for 0 ≤ θ... (answered by josmiceli)
What is sin^2 θ-1=0 using the interval 0 ≤ θ < 2 π?
 (answered by Alan3354)
What is sin(2θ)sinθ=cosθ using the interval 0 ≤ θ < 2... (answered by Alan3354,lwsshak3)
Solve the equation
Solve tan θ = 1/√3 for θ, where 0 ≤ θ... (answered by Cromlix)
Solve on 0≤   θ < 2 π, using a calculator, the equation θ cos... (answered by stanbon)
Find two values of θ, 0 ≤ θ < 2π, that satisfy the given... (answered by lwsshak3)