SOLUTION: Hey, I'm trying to prove this sin(u+v)=sin(u)cos(v)+cos(u)sin(v) and I have no idea how. Thanks :)

Question 378302: Hey, I'm trying to prove this sin(u+v)=sin(u)cos(v)+cos(u)sin(v) and I have no idea how. Thanks :)
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!



By the law of sines,



Let those three fractions equal to a constant k,



Then we have

VW = k*sin(U), UW = k*sin(V), UV = k*sin(W)

Draw altitude WX



VX = VW*cos(V) = k*sin(U)cos(V) 

UX = UW*cos(U) = k*sin(V)cos(U)

UV = VX + UX = k*sin(U)cos(V) + k*sin(V)cos(U)

UV = k*sin(W)

k*sin(W) = k*sin(U)cos(V) + k*sin(V)cos(U)

sin(W) = sin(U)cos(V) + sin(V)cos(U)

W = 180� - (U+V)

sin[180�-(U+V)] = sin(U)cos(V) + sin(V)cos(U)

and since the sine of the supplement of an angle 
equals the sine of the angle,

sin(U+V) = sin(U)cos(V) + sin(V)cos(U)

switch the factors in the last term

sin(U+V) = sin(U)cos(V) + cos(U)sin(V)

Edwin

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