SOLUTION: hi could you please help me to verify this identity
(cot^3 x - tan^3 x)/(sec^2x + cot^2x) = 2cot(2x)
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Question 376402: hi could you please help me to verify this identity
(cot^3 x - tan^3 x)/(sec^2x + cot^2x) = 2cot(2x)
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
First, we can use the pattern, , to factor the numerator:
Since cot and tan are reciprocals, cot(x)*tan(x) = 1:
Since :
We can now see that the fraction will reduce:
leaving:
Rewriting the left side using sin and cos (a common technique use in these problems) we get:
Since the right side has one term, we probably want one term on the left side, too. So we will add the fractions. Of course we need common denominators first:
Now we can subtract:
The numerator exactly matches the formula for cos(2x). The denominator is close to sin(2x). sin(2x) = 2sin(x)cos(x). If we multiply both sides by 1/2 we get: . Substituting these into our fraction we get:
We can get rid of the fraction in the denominator by multiplying the numerator and denominator by 2:
giving:
or
The fraction is cot(2x):
2cot(2x) = 2cot(2x) Done!
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