SOLUTION: i)- Solve the following equations for 0° < x < 360°.
a) 2sinx cosx = 3 sinx
b) 1 - cosx = √3
Algebra.Com
Question 374128: i)- Solve the following equations for 0° < x < 360°.
a) 2sinx cosx = 3 sinx
b) 1 - cosx = √3
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
a)
No solution.
.
..
b)
degrees and degrees
RELATED QUESTIONS
Solve for (0<=x<=360)
sin2x-cosx=-1+2sinx... (answered by Alan3354,ikleyn)
Heres 3 questions I was curious about
Given sin A = 1/3 A in Quad II, CosB = -3/5 B in (answered by drk)
If x is in quadrant I and sinx-cosx=1/3, then the value of sinx+cosx is…
A)4/3... (answered by math_tutor2020)
(1-(sinx+cosx)^2)/(2sinx)=?? (answered by Edwin McCravy)
solve... (answered by Tatiana_Stebko)
Prove the following identities:
A) cos2x/cosx+sinx = cosx - sinx
B)... (answered by Alan3354)
please help me solve this
1. prove the identity sinx/1-cosx =1/tanx
2. hence solve... (answered by Alan3354)
3-cosx=3sin^2x... (answered by stanbon)
I believe I did the problem correctly, but would like some assurance.
Proving a trig... (answered by jim_thompson5910)