SOLUTION: Find the solutions which are in the interval[0,2π) of sin5x-sinx=2cos3x

SOLUTION: Find the solutions which are in the interval[0,2π) of sin5x-sinx=2cos3x

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Question 371825: Find the solutions which are in the interval[0,2π) of sin5x-sinx=2cos3x
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
sin5x-sinx=2cos3x, same as 2cos3xsin2x = 2cos3x, from the identity
.
This means, after transposition and factoring, cos3x(sin2x - 1) = 0.
Thus cos3x = 0 or sin2x = 1,
3x = or , or 2x = .
x = or , or x = .
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