SOLUTION: How can I solve this equation and find the solutions if the solution set is greater than or equal to 0 and less than 2pi. --> {{tan^2*theta= (3/2)secant*theta}}

SOLUTION: How can I solve this equation and find the solutions if the solution set is greater than or equal to 0 and less than 2pi. --> {{tan^2theta= (3/2)secanttheta}}

Question 371397: How can I solve this equation and find the solutions if the solution set is greater than or equal to 0 and less than 2pi.
--> {{tan^2*theta= (3/2)secant*theta}}
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
tan^2(t) = (3/2)sec(t)
sin^2/cos^2 = (3/2)/cos
Multiply thru by cos^2
sin^2 = (3/2)cos
1 - cos^2 = (3/2)cos
2 - 2cos^2 = 3 cos
2cos^2 + 3cos - 2 = 0
Sub x for cos
(2x - 1)*(x + 2) = 0
x= 1/2
cos(t) = 1/2
theta = 60�, 300�
-------------
x = -2
cos(theta) = -2 Not a real number, ignore

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