You can
put this solution on YOUR website!
and

, so:
(1-cos^2X)/sinX
sin^2X/sinX --> this is why it says sinX is not zero, since if it was, we would have a "divide by zero" situation.
answer is therefore sinX
As for sin(x-pi)...what do you mean, what is the answer? You have not supplied an equation, so how can we help?
jon
You can
put this solution on YOUR website! Do you mean csc x = (cos x)(cot x)
or 1/sin x = cos x * cos x/sin x
or (1- cos^2 x)/sin x = 0,
or sin^2 x / sin x = 0
Since sin x <> 0, we have sin x = 0 (impossible)
Plz check your typing.
Whatever the given form is not so important.
You only need to simplify
(cos x)(cot x) = cos^2 x / sin x = (1-sin^2 x)/ sin x
and then try to solve by yourself.
Next, use sin (-A) = - sin A and sin(pi - A) = sin A.
We see that
sin(x -pi) = sin(-(pi -x)) = - sin(pi-x) = -sin x.
Kenny