SOLUTION: Given that f(x) =x^2-3 and g(x)=2x+1 find 1)(fg)(0) 2)(f/g)(-squareroot3)

Question 351757: Given that f(x) =x^2-3 and g(x)=2x+1 find
1)(fg)(0)
2)(f/g)(-squareroot3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given that f(x) =x^2-3 and g(x)=2x+1 find
1)(fg)(0) = f[g(0)] = f[2*0+1) = f(1) = 1^2-3 = -2
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2)(f/g)(-squareroot3) = [f(-sqrt(3)]/g[(-sqrt(3)]
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= (-sqrt(3))^2-3 / [2(-sqrt(3))+1]
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= (3-3)/[-2sqrt(3)+1]
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= 0
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Cheers,
Stan H.

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