SOLUTION: An insect population P in a certain area fluctuates with the seasons. It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it wo
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Question 350266: An insect population P in a certain area fluctuates with the seasons. It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000.
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An insect population P in a certain area fluctuates with the seasons.
It is estimated that P=17,000+4500sin pi(t)/52, where t is given in weeks. Determine the number of weeks it would take for the population to initially reach 20,000.
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20,000 = 17,000+4500sin pi(t)/52
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3000 = 4500*sin(pi*t/52)
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1/15 = sin(pi*t/52)
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(pi*t/52) = sin^-1(1/15)
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(pi/52)t = 0.0667
pi*t = 3.4692
t = 1.1043 weeks
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Cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In order for P to equal 20,000, \ =\ 3000)
, so:
\ =\ \frac{2}{3})
\ \approx\ 0.73\text{ radians})
John
My calculator said it, I believe it, that settles it
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