SOLUTION: Find the solution of sin2(theta)=cos(theta) if 0 deg. <= (theta) < 180 deg.

Algebra.Com
Question 350263: Find the solution of sin2(theta)=cos(theta) if 0 deg. <= (theta) < 180 deg.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the solution of sin2(theta)=cos(theta) if 0 deg. <= (theta) < 180 deg.
If sin2(theta) = sine squared of theta:

sub x for cos(theta)


Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=5 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.618033988749895, -1.61803398874989. Here's your graph:

x = -1/2 ± sqrt(5)/2
cos(theta) = -1/2 ± sqrt(5)/2
Use a calculator to find theta.

RELATED QUESTIONS

Find the exact value of sin (theta)/2 if cos (theta) = 2/3 and 270 deg. < (theta) < 360... (answered by jsmallt9)
31) If tan theta= 0.75, and 0 to 90 deg, evaluate sin theta; and cos... (answered by stanbon)
solve equation for solution (0 deg, 360 deg) 4 cos ^2 theta +4 cos theta = 1. I used... (answered by lwsshak3)
solve equation for solutions over the interval (0 deg, 360 deg) cos^2 theta = sin^2... (answered by Alan3354)
Use the given information to find sin 2theta, cos 2theta, and tan 2theta. #1) cos theta (answered by lwsshak3)
Solve for all values of 0, such that 0 deg < theta < 360 deg , rounding all values to the (answered by ikleyn)
solve for solutions over the interval (0 deg, 360 deg) 4 cos^2 theta + 4 cos theta = 1 (answered by stanbon)
Solve for all values of 0, such that 0 deg < theta < 360 deg , rounding all values to the (answered by ikleyn)
If sin(theta) = 7/24' and cos(theta) < 0, find the exact value of tan(theta) (answered by Alan3354)