SOLUTION: Given that cos(x)=-1/4(7^0.5) where pi < x < 3/2pi find sin(x)
Quick walkthrough would be appreciated
Thanks in advance
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Question 346794: Given that cos(x)=-1/4(7^0.5) where pi < x < 3/2pi find sin(x)
Quick walkthrough would be appreciated
Thanks in advance
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Recall that 
, hence:
\ =\ \pm\sqrt{1\ -\ \cos^2(x)})
\ =\ \pm\sqrt{1\ -\ \frac{7}{16}})
\ =\ \pm\sqrt{\frac{9}{16}})
\ =\ \pm\frac{3}{4})
But you restricted 
the the third quadrant, 
. Sin is negative in the third quadrant, so:
\ =\ -\frac{3}{4})
John
My calculator said it, I believe it, that settles it
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