SOLUTION: A) Find the value of Sin^-1 (-1/2) B) Find the value of tan(Tan^-1 1/2)

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Question 341400: A) Find the value of Sin^-1 (-1/2)
B) Find the value of tan(Tan^-1 1/2)

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming you can use your calculator.

Sin^-1 (-1/2) would be equivalent to sin^-1 (-.5).

Enter -.5 in your calculator and get Sin^-1 of it.

That should be equal to -30 degrees.

Tan (Tan -1 (1/2)) should be equal to 1/2 since you are finding the degree that has a tangent of 1/2 and then you are finding the tangent of that degree.

Follow it through with your calculator.

Tan^-1 (1/2) is the same as Tan^-1 (.5).

Enter .5 in your calculator and get Tan^-1 of it.

That should be equal to 26.56505118 degrees.

Put that in your calculator and get the Tan of it.

That should be equal to .5

If Sin(x) = y, then Sin^-1 (y) = x
If Cos(x) = y, then Cos^-1 (y) = x
If Tan(x) = y, then Tan^-1 (y) = x

These are inverse functions of each other.

This is no different then if x%5Ey+=+z, then z%5E%281%2Fy%29+=+x

Put number into that equation to see how it works.

2%5E6+=+64
64%5E%281%2F6%29+=+2

Note that 64%5E%281%2F6%29 is the same as root%286%2C64%29

The exponents are being clipped.

They should be 1%2Fy and 1%2F6 respectively, depending on whether the denominator of the fractional exponent is a y or a 6.