SOLUTION: solve this triangle: a=32.0 b=40.0 C=71 degrees 45'
Algebra.Com
Question 34007: solve this triangle: a=32.0 b=40.0 C=71 degrees 45'
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
C^2=A^2+B^2-2ABCOS ©
4561.159499
67.53857416
C/SIN©=B/SIN(B)
SIN(B)=BSIN©/C
0.562345411
ANGLE (B)= 34.25
ANGLE A =180-71.75-34.25=72
RELATED QUESTIONS
How do you solve this triangle: a=32.0 b=40.0 c=71 degrees... (answered by Prithwis)
Solve the equation on the interval [0,360) {{{ 2Sin^2 (x)+ 3Sin(x)+1=0 }}}
a)45(degrees) (answered by jim_thompson5910)
Solve the following triangle C=80 degrees b=7 and A=45 degrees what is a,c and... (answered by stanbon)
Which of the following is a solution to 2sin^2x+sinx-1=0?
a. 45 degrees
b. 200... (answered by MathLover1)
What is the value of arctan (-√3)?
a. 60 degrees
b. 90 degrees
c.-60 degrees
d. 0 (answered by Boreal)
What is the value of arctan(-√3)?
a. 60 degrees
b. 90 degrees
c. -60 degrees
d. 0 (answered by MathLover1)
Find all solutions in the interval [0,360]
{{{ sin(4t)=sqrt(3) /2 }}}
a)0 degrees, 45 (answered by Alan3354)
If the sides of a right triangle are a=5 and b=8, the angle B is?
a.) 59 degrees, 2',... (answered by Fombitz)
Solve the triangle for little a GIven: (answered by richard1234)