SOLUTION: Solve 2sin x + sqrt3 < 0 for 0 =< x =< 2pi

Algebra.Com
Question 337101: Solve 2sin x + sqrt3 < 0 for 0 =< x =< 2pi
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!



Find the values when
,
So then

.
.
.

RELATED QUESTIONS

how do i solve 2sin(x) + sqr3 = 0 for 0 < x <... (answered by ikleyn)
solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and... (answered by lwsshak3)
Please solve the equation for the interval [0, 2pi]: {{{2sin^2(x)-sin(x)-1=0}}}... (answered by josgarithmetic)
Please solve for x... (answered by Alan3354)
I need to solve this equation for the interval [0, 2pi) : -sin^2(x) =... (answered by Boreal)
solve: 2sin x - 3 =... (answered by Alan3354)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)
solve 12sin^2(x)+2sin(x)-2=0 where x is in radians between 0 and... (answered by Alan3354)
solve 2sin x + sqrt 3<0 for 0<= x < 2pi a)4pi/3 < x < 5pi/3 b)2pi/3 < x < 4pi/3... (answered by stanbon)