SOLUTION: I need help solving the following equation for 0(<=) X (<=)2pi
2sinXcosX= (sqrt 2)cosX
Algebra.Com
Question 337033: I need help solving the following equation for 0(<=) X (<=)2pi
2sinXcosX= (sqrt 2)cosX
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
.
.
.
What are the two values of that have this value for ?
RELATED QUESTIONS
I need help solving the following equation for 0(<=) X (<=)2pi
tan^2 X +... (answered by Fombitz)
I need help solving the following equation for 0(<=) X (<=)2pi
2cos^2X - 3cosX-2=0... (answered by Fombitz)
I need to solve the following for x where degrees 0 (answered by Edwin McCravy)
Calculating trigonometric equations for x in radians.
Find all the solutions of the... (answered by greenestamps)
I am stuck on the following question:
Solve for x in the equation: (1+sinx)/cosx +... (answered by lwsshak3)
Solve cos2x = -cosx for the interval 0 ≤ x <... (answered by MathLover1)
Solve cos2x=-cosx for the interval 0 ≤ x <... (answered by MathLover1)
I need to solve this equation for the interval [0, 2pi) :
-sin^2(x) =... (answered by Boreal)
How do I solve the following question: cos square x - 2sinxcosx - sin square x =... (answered by richard1234)