SOLUTION: For my college Pre-calc. class I need to prove this: tan^3x-1/tanx-1 = sec^2x+tan x

Question 32892: For my college Pre-calc. class I need to prove this:
tan^3x-1/tanx-1 = sec^2x+tan x
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
tan^3x-1/tanx-1 = sec^2x+tan x..USING....A^3-B^3=(A-B)(A^2+AB+B^2)
LHS=[{TAN(X)-1}{TAN^2(X)+TAN(X)+1}]/[(TAN(X)-1]=SEC^2(X)+TAN(X)=RHS...SINCE 1+TAN^2(X)=SEC^2(X)
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