SOLUTION: solve x(x-1) = 3x + 2 I got x^2 - x = 3x + 2 x^2 - 4x

SOLUTION: solve x(x-1) = 3x + 2 I got x^2 - x = 3x + 2 x^2 - 4x - 2 = 0 im stuck!

Question 32646: solve x(x-1) = 3x + 2
I got x^2 - x = 3x + 2
x^2 - 4x - 2 = 0
im stuck!
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
x(x-1) = 3x + 2
=> x^2-x = 3x+2
=> x^2-x-3x-2 = 0
=> x^2-4x-2 = 0
The roots of quadratic equation ax^2+bx+c=0 are
[-b+sqrt(b^2-4ac)]/2a and [-b-sqrt(b^2-4ac)]/2a;
Here a=1, b=-4 and c=-2
The roots of this equation are:
[4+sqrt(16+8)]/2 and [4-sqrt(16+8)]/2
=> [4+sqrt(24)]/2 and [4-sqrt(24)]/2
=> x=2+sqrt(6) and x=2-sqrt(6)

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