SOLUTION: I am trying to solve for t:
{{{ 2t ( sin (t^2+1 ) + cos ( t^2+1 ))^2 - 4tsin ( t^2+1 ) cos ( t^2+1 ) = 2 }}}
I have no idea where to start. Thank you for you help.
Algebra.Com
Question 30793: I am trying to solve for t:
I have no idea where to start. Thank you for you help.
Answer by Fermat(136) (Show Source): You can put this solution on YOUR website!
Yo gonna kick yo'sel
To simplify things,let u = t²+1
we can then write out your eqn as,
2t(sinu + cosu)² - 4t.sinu.cosu = 2
2t(sin²u + 2sinu.cosu + cos²u) - 2t.sin2u = 2
2t(1 + sin2u) - 2t.sin2u = 2
2t + 2t.sin2u - 2t.sin2u = 2
2t = 2
t = 1
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