SOLUTION: Find the distance between the lines 2x+3y-15=0 and -3x-2y=8
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Question 302863: Find the distance between the lines 2x+3y-15=0 and -3x-2y=8
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the distance between the lines 2x+3y-15=0 and -3x-2y=8
m = -2/3
b1 = 5
b2 = -4
d = 9*sin(arctan(-2/3) + 90)
d =~ 7.488
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