SOLUTION: prove each of the following identities algebraically a. cosA+cosA tan squareA=secA b.cosA(secA-cscA)=1-cotA c.Prove the identity sin squareA divided 1-cosA=secA+1 divided by secA

Question 29855: prove each of the following identities algebraically a. cosA+cosA tan squareA=secA
b.cosA(secA-cscA)=1-cotA
c.Prove the identity sin squareA divided 1-cosA=secA+1 divided by secA
d.Verify sin square x+cos square x=1 for x=5pi divided by 3.Graph y=sin square
x+cos square x and describe the result.Also explain the result.
Thank you so much . This is my first attempt at pure math so i am very bad at it.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
prove each of the following identities algebraically a. cosA+cosA tan squareA=secA
LHS=COS A (1+TANSQUARE A)=COS A * SECSQ.A=COS A/COSSQ.A =1/COS A = SEC A =RHS.
b.cosA(secA-cscA)=1-cotA
LHS=COS A*1/COS A-COS A/SIN A = 1-COT A = RHS
c.Prove the identity sin squareA divided 1-cosA=secA+1 divided by secA
LHS = (1-COSSQ.A)/(1-COS A)=1+COS A
RHS={(1/COS A) + 1 }/(1/COS A)=(1+COS A)COS A/COS A=1+COS A=LHS
d.Verify sin square x+cos square x=1 for x=5pi divided by 3.
SINSQ.5PI + COSSQ. 5PI = SINSQ.(2*2PI+PI) + COSSQ.(2*2PI+PI)
=SINSQ.PI + COSSQ. PI = (0)^2 + (-1)^2 =0+1=1
Graph
y=sin square x+cos square x and describe the result.

Also explain the result...WE GET A LINE PARALLEL TO XAXIS AT A DISTANCE OF PLUS ONE UNIT FROM IT.THAT IS Y=1..WHATEVER MAY BE THE VALUE OF X .

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