SOLUTION: I need to solve for X over interval {0, 2pi) 4cos2x=sqrt3 I tried dividing out 4 but then am stuck with cos2x(which is an identity) = sqrt3/4. Then im left with 2cos^2x

SOLUTION: I need to solve for X over interval {0, 2pi) 4cos2x=sqrt3 I tried dividing out 4 but then am stuck with cos2x(which is an identity) = sqrt3/4. Then im left with 2cos^2x - 1

Question 293272: I need to solve for X over interval {0, 2pi)
4cos2x=sqrt3
I tried dividing out 4 but then am stuck with cos2x(which is an identity) = sqrt3/4.
Then im left with 2cos^2x - 1 = sqrt3/4.
Should I turn the cos2x into its identity before dividing out 4?
If anyone can help me get on track that would be great!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I need to solve for X over interval {0, 2pi)
4cos2x=sqrt3
---
cos(2x) = (1/4)sqrt(3)
---
Take the arcos of each side to get:
2x = arcos[(sqrt(3)/4]
---
2x = 64.34 degrees
x = 32.17 degrees
======================
Cheers,
Stan H.
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