SOLUTION: This trig. identity is also hard. Can you help me equal it? We are only allowed to work on one side of the problem.
cos/sec + sin/csc = sec^2 - tan^2
Algebra.Com
Question 282268: This trig. identity is also hard. Can you help me equal it? We are only allowed to work on one side of the problem.
cos/sec + sin/csc = sec^2 - tan^2
Answer by xachu4u(10) (Show Source): You can put this solution on YOUR website!
Is it not easy?
L.H.S is cos^2 + sin^2 , i.e =1
R.H.S is also 1 since
1 + tan^2 = sec^2
RELATED QUESTIONS
I also need help on this trig. identity as well.
sin^2 - 1 = -cos^2
Once again thanks!... (answered by jim_thompson5910)
I need help with verifying this trig identity. The problem is sec^4x-tan^4x / sec^2+... (answered by solver91311)
I need to prove the following identity. Basically, I need to choose one side of the... (answered by tutor_paul)
I think my problem with these kinds of questions is that I’m having a hard time... (answered by jsmallt9)
this is my problem that i cannot solve.. sin^4 - cos^4 = 2sin^2 - 1
we can only work on... (answered by mananth)
I was helping a friend with her trig homework and we both got stuck on this one problem.... (answered by nyc_function)
Our problem was to find all the trig functions of which angle θ equaled one and were (answered by lwsshak3)
why is it important to work only 1 side of a trig identity?
Can you show an example... (answered by ikleyn)
Why is it important to work only 1 side of a trig identity?
---
Can you show an... (answered by Alan3354)