SOLUTION: Hi. I have a question about Pythagorean identities. I do not understrand how to write the espression as an integer. The problem is: {{{Csc^2}}}{{{(3alpha)}}}{{{""-""}}}{{{Cot^2}

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Question 276355: Hi. I have a question about Pythagorean identities. I do not understrand how to write the espression as an integer. The problem is:

Thanks in advance.

Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I do not understrand how to write the espression as an integer. The problem is:
csc^2 3alpha - cot^2 3alpha
----------------------------
I'm not sure what you mean by "write...as an integer."
This can be simplified:
csc^2 3alpha - cot^2 3alpha
= 1/sin^2 - cos^2/sin^2
= (1-cos^2)/sin^2
= sin^2/sin^2
= 1

Answer by Edwin McCravy(20064)   (Show Source): You can put this solution on YOUR website!

First let's learn where the Pythagorean identities came from,
namely the Pythagorean theorem:



By the Pythagorean theorem:



Divide through by 







That's the first Pythagorean identity:

-------------------------------------



Divide through by 







That's the second Pythagorean identity:

-------------------------------------



Divide through by 







That's the third Pythagorean identity:

-------------------------------------

Be sure to memorize all three of them.  Usually we write them
this way, so they're easier to learn:





--------------------------------------

Those identities are true for ALL angles 

So for



Since the third Pythagorean identity

 

is true for ALL angles , let , then



So we can replace  by 

So your problem:



becomes:



then the "cotangent squared"s cancel:



and that just leaves 1, which is an integer.

Edwin

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