SOLUTION: how do you solve [2x^3y^-3z^5][4x^-3y^-2z^-1]
Algebra.Com
Question 271019: how do you solve [2x^3y^-3z^5][4x^-3y^-2z^-1]
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do you solve [2x^3y^-3z^5][4x^-3y^-2z^-1]
-----
= 2x^3y^-3[4x^-3y^-2z^-1] - 3z^5[4x^-3y^-2z^-1]
-----
= 8x^0*y^-5*z^-1 - 12x^-3*y^-2*z^4
-----
= 8y^-5*z^-1 - 12x^-3*y^-2*z^4
-----
= [8/y^5*z] - [12z^4/x^3*y^2]
=====
Cheers,
Stan H.
RELATED QUESTIONS
How do you solve this system using elimination?
-2x+5y-3z=7
4x-3y+2z=4... (answered by t0hierry,greenestamps)
solve each system
x+y-z= -1
4x-3y+2z= 16... (answered by venugopalramana)
solve:
3x+3y+3z+w=0
2x+2y+3z+2w=0... (answered by Alan3354)
Solve the system of equations:
-3x + y - z = -10
-4x + 2y + 3z = -1
2x + 3y - 2z... (answered by robertb)
2x+3y-z=4
3x+2y+2z=6
4x-y+3z=5
solve in three... (answered by josmiceli)
Solve each system
2x+y+z=14
-x-3y+2z=-2... (answered by MathLover1)
3x – 2y + 3z = 8
2x + y – z = 1
4x – 3y + 2z = 4
solve by... (answered by richwmiller)
Solve the system using any algebraic method.
1.
x-y+z=5
2y+3z=14
-3y+2z=5... (answered by aswathytony)
Solve the system of equations:
2x-3y+2z=-1
x+2y=14... (answered by Alan3354)