SOLUTION: solve the equation in the interval [0,2Pi). sin(pi-x)=1

Question 250620: solve the equation in the interval [0,2Pi). sin(pi-x)=1
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
We start with
.
Here is one way. Replace (pi-X) with A.
We have
.
At what values of A is the sin = 1?
only.
Substitute (pi-X) back for A and we get
.
Solving for X, we get
.
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