SOLUTION: SQRT -4(SQRT 36 cos 0 degrees/4 sin 90 degrees)-144+(5x5x5)) -16i/2

Algebra.Com
Question 250600: SQRT -4(SQRT 36 cos 0 degrees/4 sin 90 degrees)-144+(5x5x5))
-16i/2

Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
here is the original equation

One part at a time
the numerator is:
= -24
the denominator is:
= 4
numerator over denominator is:

So, we have
= 5i.
Now,
5i -16pi/2 is the answer.

RELATED QUESTIONS

Evaluate sin 0 degrees + 2 cos 0 degrees + 3 sin 90 degrees + 4 cos 90 degrees + 5 sec 0... (answered by MathLover1)
If sinθ = (sqrt(7)/4) and, cos < 0. What is tanθ? 1) (4/3) 2) -(sqrt(7)/4) (answered by stanbon)
Solve for all 0 degrees less than or equal to x less than 360 degrees. 3tan x- sqrt( 3... (answered by lwsshak3)
find sin 0 if cos 0=-2/3 and 90 degree<0>180... (answered by stanbon)
Angels between 0 degrees and 90 degrees sin 150 degrees = sin ? sin 150 degrees = cos... (answered by stanbon)
If {{{ 0 <= x <= 90}}}°, prove that {{{ 1 <= sin(x) + cos(x) <= sqrt(2)... (answered by htmentor)
Solve the following when 0 degrees is less then or equal to x less the 360 degrees A)... (answered by stanbon)
Evaluate sin 0 degrees+cos 180 degrees-sin 270... (answered by stanbon,solver91311)
Please help me with this! If: z=4(cos 50 degrees + i sin 50 degrees) and w=2(cos 340... (answered by Edwin McCravy)