SOLUTION: directions: find the standard form of the equation of each circle center at (0,3) and containing the point (3,7) please help me solve.

Question 247371: directions: find the standard form of the equation of each circle
center at (0,3) and containing the point (3,7)
please help me solve.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
I haven't done this in a while so here goes.
formula for the center of a circle
(x-h)^2+(y-3)^2=r^2
(0,3) is the center (h,k)
so far we have
(x-0)^2+(y-3)^2=r^2
r= the distance from the center to the circle
the point 3,7 is on the circle
a^2+b^2=r^2
(7-3)^2+(3-0)^2=r^2
16+9=25
(x-0)^2+(y-3)^2=25
now to put it in standard form

x^2+(y-3)^2=25

RELATED QUESTIONS
Need help with a question. Find the general form of the equation of the circle: Center... (answered by MathLover1)

Find the general form of the equation of the circle with center at the point (2, -3)... (answered by Alan3354)

For A and B, find the standard form of the equation of each circle. A. Center (1,0)... (answered by mananth,MathTherapy,timofer)

1. Write the following equation of a circle in standard form: x^2+y^2-4x +2y+3=0 2.... (answered by solver91311)

Find the equation of the circle (in standard form) with radius 7 and center... (answered by jynobauan)

can u please help me with this Write the equation of the circle with center (-3,-2)... (answered by Fombitz)

Find the standard form of the equation of the circle having the following properties: (answered by ikleyn,josgarithmetic,math_tutor2020)

Find the equation of the circle (standard form) with center at (3,-4) and passing through (answered by Alan3354)