SOLUTION: please help me to solve this quadratic equation:
Give the propeties for the equation x^2+y^2+8x-2y+15=0, center:
here are the possible answers:
a)(4,1)
b)(-4,1)
c)(-8,2)
Algebra.Com
Question 244126: please help me to solve this quadratic equation:
Give the propeties for the equation x^2+y^2+8x-2y+15=0, center:
here are the possible answers:
a)(4,1)
b)(-4,1)
c)(-8,2)
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x^2+y^2+8x-2y+15=0
(x^2+8x+16) + (y^2-2y+1) + 15 = 17
(x+4)^2 + (y-1)^2 = 2
Center is (-4,1)
radius is sqrt(2)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You need to complete the square on both
and
, then factor the perfect squares.
First, move the constant to the RHS:
Rearrange:
Divide the coefficient on the
-term by 2, then square the result. Add this result to both sides of the equation.
Do the same thing for the
-term:
Factor
and
and then replace these two trinomials in your equation with the squared binomial representation.
You can then determine the center by inspection since a circle centered at
with radius
is defined by:
Pay careful attention to the signs on your center coordinates.
John

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