SOLUTION: find the area of a parallelogram with an angle of 65 degrees 16 minutes included between two sides of 19 and 23.

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Question 243871: find the area of a parallelogram with an angle of 65 degrees 16 minutes included between two sides of 19 and 23.
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
I will assume the horizontal side is 23 and the slanting side is 19.

This should work either way.

Area of a parallelogram is equal to base * height.

The base would be equal to 23.

The height is what you have to find.

The angle is 65 degrees 16 minutes which equates to an angle of 65 + 16/60 degrees which equals 65.2666666667 degrees.

Since the sine of this angle is equal to opposite / hypotenuse, and hypotenuse is equal to 19, and opposite equals height, then this formula becomes:

sine (angle) = height / 19 which makes:

height = 19 * sine (angle).

since the angle iss 65.26666666667 degrees, then this formula becomes:

height = 19 * sine (65.2666666667) which becomes:

height = 19 * .908264919 which becomes:

height = 17.25703345

this makes the area = to 17.25703345 * 23 = 396.9117694 square units.

assuminb the base was 19 and the slant was 23, then this formula becomes:

height = 23 * .908264919 which becomes:

height = 20.89009313

this makes the area = t 20.89009313 * 19 = 396.9117694 square units.

the area is the same as it should be.

your parallelogram would look something like this:


                                23 units
                      xxxxxxxxxxxxxxxxxxxxxxxxxxxx
                       x                         xx
                        x                        x x  19 units
                         x        height -->     x  x
                          x                      x   x <---65.267 degrees
                           xxxxxxxxxxxxxxxxxxxxxxxxxxxx




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