SOLUTION: please help me:
The range of F in F(x)=2sinx;-pi/2<x<pi is :
HERE ARE THE POSSIBLE ANSWERS:
a)-2<_F(x)<_2
b)-2<_F(x)<_0
c)F(x)<_2
Algebra.Com
Question 242933: please help me:
The range of F in F(x)=2sinx;-pi/2
HERE ARE THE POSSIBLE ANSWERS:
a)-2<_F(x)<_2
b)-2<_F(x)<_0
c)F(x)<_2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
If you graph , you get
and you can see that the min y value is -2 while the max y value is 2. So the range is making the answer a)
Another way you can do it is look at a table of values for 2*sin(x) and determine the max/min values.
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