SOLUTION: PLEASE HELP SOLVE THIS CIRCULAR FUNCTIONS AND THEIR GRAPHS: What is the phase shift of F(x)=3 sin (2x-4)? HERE ARE THE POSSIBLE ANSWERS: a)2 right b)2 left c)4 right

Question 240804: PLEASE HELP SOLVE THIS CIRCULAR FUNCTIONS AND THEIR GRAPHS:
What is the phase shift of F(x)=3 sin (2x-4)?
HERE ARE THE POSSIBLE ANSWERS:
a)2 right
b)2 left
c)4 right
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
For sin and cos, if you write the equation in the form:

The numbers you find for A, B, C and D will tell you a lot about the function:
A = the amplitude.
B = /period or 360/period depending on if you are using radians or degrees
C = the vertical shift
D = the horizontal (or phase shift)

Your equation is almost in the right form. We just need to factor the 2 in the argument:

Now we can "read" the equation:
A = 3 so the amplitude is 3.
B = 2 so we could use /period to find the period if we wanted it.
C is missing so it is zero. There is no vertical shift.
D = 2 so the horizontal or phase shift is 2 (to the right). (A negative D would be a shift to the left.)
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