SOLUTION: Adult tickets for a play cost $25 each and the childrens tickets cost $15 each. The total receipts were $7,200 and the total attendenct was 400. How many adults and how many childr

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Adult tickets for a play cost $25 each and the childrens tickets cost $15 each. The total receipts were $7,200 and the total attendenct was 400. How many adults and how many childr      Log On

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Question 235401: Adult tickets for a play cost $25 each and the childrens tickets cost $15 each. The total receipts were $7,200 and the total attendenct was 400. How many adults and how many children attended?
Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
a=c=400 or a=400-c
25a+15c=7,200
25(400-c)+15c=7,200
10,000-25c+15c=7,200-10,000
-10c=-2,800
c=-2,800/-10
c=280 ans. for the number of children tickets sold.
400-280=120 adult tickets were sold.
Proof:
25*120+15*280=7,200
3,000+4,200=7,200
7,200=7,200