# SOLUTION: write the standard form of the equation of the circle that is tangent to x= -2 and has its center at (2, -4)

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 Question 218932: write the standard form of the equation of the circle that is tangent to x= -2 and has its center at (2, -4)Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!the standard form for a circle is,,,(x-h)^2 +(y-k)^2 = r^2 . with (h,k) as center of circle,,and r as radius . with center at (2, -4),,,,,h= 2,,,k= -4,,,and radius is the x distance from center to x=-2,,,|(-2-2)| = |(-4)| = 4 . substituting, (x-2)^2 + (y-(-4) )^2 =4^2 =16 . (x-2)^2 +(y+4)^2 = 16,,,,answer . . a rough sketch shows how this is possible on the x-y coordinate system. . .