SOLUTION: a triangular shelf is to be placed in a curio cabinet whose sides meet at an angle of 105 degrees.if the edges of the shelf along the sides measure 56 centimeters and 65 centimeter

Question 216717: a triangular shelf is to be placed in a curio cabinet whose sides meet at an angle of 105 degrees.if the edges of the shelf along the sides measure 56 centimeters and 65 centimeters,how long is the outside edge of the shelf?round to the nearest tenth.
Found 2 solutions by rfer, rfadrogane:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
c^2=a^2+b^2
c^2=56^2+65^2
c^2=3136+4225
c^2=7361
c=85.8 cm
Answer by rfadrogane(214) (Show Source): You can put this solution on YOUR website!
a triangular shelf is to be placed in a curio cabinet whose sides meet at an angle of 105 degrees.if the edges of the shelf along the sides measure 56 centimeters and 65 centimeters,how long is the outside edge of the shelf?round to the nearest tenth.
Use Cosine Law.
c^2 = a^2 + b^2 - 2ab cos (included angle)
c = sq. rt.[56^2 + 65^2 - 2(56)(65)cos 105 deg.]
c = 96.2-cm ---answer.
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