SOLUTION: I'm actually in pre-calc...i just couldn't find a category for it.
here's my problem!
A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 de
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Question 215032: I'm actually in pre-calc...i just couldn't find a category for it.
here's my problem!
A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer.
Found 2 solutions by Alan3354, rfadrogane:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A ship travels 58 km on a bearing of 20 degrees, and then travels on a bearing of 110 degrees for 133 km. Find the distance from the starting point to the end of the trip, to the nearest kilometer.
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2 sides of a triangle are given, 58 and 133 km.
The change in heading from 020º to 110º is 90º, so it's a right triangle.
Use Pythagoras:
s = 124 km
Answer by rfadrogane(214) (Show Source): You can put this solution on YOUR website!
Since it forms a right triangle after you simplify, therefore:
d = sq. root (58^2 + 133^2)
d = 145-km
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