SOLUTION: The height of a ball thrown directly up from a roof 144 ft high with an initial velocity of 128 ft/sec is given by the formula y= 144 + 128t- 16t^2. What is the maximum height atta
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Question 215013: The height of a ball thrown directly up from a roof 144 ft high with an initial velocity of 128 ft/sec is given by the formula y= 144 + 128t- 16t^2. What is the maximum height attained by the ball?
At first, the problem looked to be a quadratic equation... but then I assumed it had something to do with the velocity formula. Essentially, I am a bit lost.
Thanks in advance!
-B
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: I'm going to use the variable 'x' instead of 't'.
Start with the given equation.
Rearrange the terms.
In order to find the vertex, we first need to find the x-coordinate of the vertex.
To find the x-coordinate of the vertex, use this formula: .
Start with the given formula.
From , we can see that , , and .
Plug in and .
Multiply 2 and to get .
Divide.
So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .
Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.
Start with the given equation.
Plug in .
Square to get .
Multiply and to get .
Multiply and to get .
Combine like terms.
So the y-coordinate of the vertex is .
So the vertex is
.
This means that the max height is 400 feet (since the max/min is the y coordinate of the vertex). This max height occurs when (since x=4 at the vertex and I used 'x' instead of 't')
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