SOLUTION: Having trouble figuring out how to due this can someone help please... Use integration by substitution to find.. int(3x^2-2)(x^3-2x)^7 dx have no clue thanks

Question 203602: Having trouble figuring out how to due this can someone help please...
Use integration by substitution to find..
int(3x^2-2)(x^3-2x)^7 dx
have no clue thanks

Found 2 solutions by vleith, stanbon:
Answer by vleith(2517) (Show Source):
You can put this solution on YOUR website!
Use this site for this type of stuff
http://www88.wolframalpha.com/input/?i=(3x^2-2)(x^3-2x)^7
Then scroll down to the Indefinte Integral and click the "Show Steps"

Answer by stanbon(48558) (Show Source):
You can put this solution on YOUR website!
Having trouble figuring out how to due this can someone help please...
Use integration by substitution to find..
int(3x^2-2)(x^3-2x)^7 dx
----------------------------
Let u = x^3-2x
Then du = 3x^2-2 dx
------------------------
Substitute into your original integral and you get:
int[u^7 du]
---
Integrate wrt u to get:
(1/8)u^8 + C
--------------------
Substitute back into "x" to get:
= (1/8)(x^3-2x)^8 + C
================================
Cheers,
Stan H.