SOLUTION: I'm trying to plot points on a graph. the problem is y=3sec4x. I have all the points but one. I'm stuck at 5 pi/2. I have no idea how to find this on the unit circle. Explain plz?
Algebra.Com
Question 194801: I'm trying to plot points on a graph. the problem is y=3sec4x. I have all the points but one. I'm stuck at 5 pi/2. I have no idea how to find this on the unit circle. Explain plz?
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
From the positive x-axis to the positive y-axis:
, then from the positive y-axis to the negative x-axis another
for a total of
. Then one more quarter circle,
. All the way back to the beginning:
. Yep,
is the same thing as
. In fact, all angles of the form
are the same angle
John

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I'm trying to plot points on a graph. the problem is y=3sec4x. I have all the points but one. I'm stuck at 5 pi/2. I have no idea how to find this on the unit circle. Explain plz?
-------------------------------
Try cos(5pi/2) which is the same as cos(pi/2) = 0
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Since sec is the inverse of cos, sec(5pi/2) is undefined.
---------------
Cheers,
Stan H.
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