SOLUTION: Solve the equation cos ?(2sin ? +√3)(-√2 cos ? + 1) = 0 for 0 = x = 2π.
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Question 194684: Solve the equation cos ?(2sin ? +√3)(-√2 cos ? + 1) = 0 for 0 = x = 2π.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I think you meant:
\right)\left(2\sin(x) + \sqrt{3}\right)\left(\sqrt{2}\cos(x) + 1\right)=0)
on the interval:
Use the Zero Product Rule:
Either
 = 0)
or
 + \sqrt{3} = 0 \ \ \Rightarrow\ \ \sin(x) = - \frac{\sqrt{3}}{2})
or
 + 1 = 0 \ \ \Rightarrow\ \ \cos(x) = \frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2})
Each value will result in two angles on the given interval for a total of 6 roots to the equation.
John
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