SOLUTION: I do not get how to prove that left side is equal to right side: tan2@ - sin2@ = sin2@*tan2@ </pre>

Question 194509: I do not get how to prove that left side is equal to right side:
tan²@ - sin²@ = sin²@*tan²@

Found 2 solutions by RAY100, Edwin McCravy:
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
tan^2a -sin^2a = sin^2a * tan^2a,,,,let a = theta
,
but tan = sin / cos
,
sin^2 a/cos^2a -sin^2a = sin^2a *tan^2a
,,
remember cos^2 = sin^2 =1,,, cos^2a = 1=sin^2a
,
sin^2a / ( 1-sin^2a) - sin^2a = sin^2a * tan^2a
,
using lcd = (1-sin^2a)
,
( sin^2a -sin^2a (1-sin^2a) )/ (1-sin^2a) = sin^2a *tan^2a
,
( sin^2a -sin^2a +sin4a ) (1-sin^2a) = sin^2a * tan^2a
,
but cos^2a = 1 - sin^2a
,
sin^4a / cos^2a = sin^2a * tan^2a
,
with tan = sin / cos
,
sin^2a * tan^2a = sin^2a * tan^2a
Answer by Edwin McCravy(20066) (Show Source): You can put this solution on YOUR website!
Edwin's solution:

tan²@ - sin²@ = sin²@*tan²@ sin²@ sin²@ ----- - ----- cos²@ 1 sin²@ sin²@*cos²@ ----- - ----------- cos²@ 1*cos²@ sin²@ - sin²@*cos²@ ------------------- cos²@ sin²@(1 - cos²@) ------------------ cos²@ sin²@(sin²@) --------------- cos²@ /sin²@\ | ------| (sin²@) \cos²@/ tan²@*sin²@ sin²@*tan²@ Edwin

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SOLUTION: I do not get how to prove that left side is equal to right side: tan<sup>2</sup>@ - sin<sup>2</sup>@ = sin<sup>2</sup>@*tan<sup>2</sup>@ </pre>