SOLUTION: I need your help in how to solve the question Solve over the interval [0,360] sin 2x = cos 2x +1

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Sin 2x = Cos 2x + 1

2 Sin x Cos x = Cos 2x + 1

2 Sin x Cos x = Cos^2 x – Sin^2 x + Cos^2 x + Sin^2 x

2 Sin x Cos x = 2 Cos^2 x

Cancel out the 2 Cos x (giving solutions for Cos x = 0 are 90 and 270)

Sin x = Cos x gives solutions 45 and 225

Therefore the solutions are 45, 90, 225 and 270 degrees.