SOLUTION: I had a test today, and could not crack this problem I really would appreciate the help so I can understand it later on.
Prove:
cotx*cosx=cotx-cosx
first i found a commo
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Question 187494: I had a test today, and could not crack this problem I really would appreciate the help so I can understand it later on.
Prove:
cotx*cosx=cotx-cosx
first i found a common denominator, but after that i was stuck.
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Prove:
cotx*cosx=cotx-cosx
I don't think it is equal.
cos/tan = cot - cos
cos = 1 - cos*tan
cos = 1 - sin That is not true.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming that you want to prove that is an identity right?
There's a problem here, the equation:
is NOT an identity (graph the two sides if you aren't sure)
--------------
For example, let
Start with the given equation.
Plug in
Evaluate the given trig functions (note: I'm working in radian mode).
Simplify. Clearly the two sides are NOT equal.
Since , this means that the equation is NOT true for ALL values of "x". So the equation is NOT an identity.
So either there's a typo or you were supposed to disprove it being an identity. My guess would be that there's a typo in there somewhere.
Note: if you change the "cot" to "csc" and "cos" to "sin" on the right, you'll get which is an identity
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