SOLUTION: Use the discriminant to describe the roots of the equation: 16x^2=25 It seems like there are a few numbers missing. What do I do?

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Question 185377This question is from textbook saxon algebra 2
: Use the discriminant to describe the roots of the equation: 16x^2=25
It seems like there are a few numbers missing. What do I do?
This question is from textbook saxon algebra 2

Found 3 solutions by Alan3354, feliz1965, stanbon:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
16x^2=25
It seems like there are a few numbers missing. What do I do?
Any "missing" numbers are zeroes.
------------
16x^2 + 0x - 25 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1600 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.25, -1.25. Here's your graph:



Answer by feliz1965(151)   (Show Source): You can put this solution on YOUR website!
Use the discriminant to describe the roots of the equation: 16x^2=25
It seems like there are a few numbers missing. What do I do?
Subtract 25 from both sides.
16x^2 - 25 = 0
This tells me that a = 16, b = 0 and c = -25
When a variable is missing, replace that variable with 0.
Here is the discriminant: b^2 - 4ac
We now plug and chug.
Can you finish now?


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Use the discriminant to describe the roots of the equation: 16x^2=25
--------------------------------------------------------------------
Rearrange:
16x^2 + 0x -25 = 0
a = 16
b = 0
c = -25
================
discriminant = b^2 - 4ac
0^2 - 4*16*-25 = 1600
-----------------------
Since 1600 is greater than zero there are two unequal Real Numbers.
======================================================================
Cheers,
Stan H.

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