SOLUTION: I was given the question to find the angles, Sin^2 theta = 2cos theta + 2 So I get 1-cos^2 theta = 2cos theta + 2 I think putting this into Ax^2 + Bx +C = 0 would work but is t

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: I was given the question to find the angles, Sin^2 theta = 2cos theta + 2 So I get 1-cos^2 theta = 2cos theta + 2 I think putting this into Ax^2 + Bx +C = 0 would work but is t      Log On

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Question 1838: I was given the question to find the angles,
Sin^2 theta = 2cos theta + 2
So I get
1-cos^2 theta = 2cos theta + 2
I think putting this into Ax^2 + Bx +C = 0 would work but is this
Cos^2T + 2CosT +1 = 0
And then plug into quadratic??


Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
from cos^2T + 2cosT +1 = 0, let x=cosT, therefore x%5E2+%2B+2x+%2B+1+=+0. You can factorise this (or put it in the formula)...
factorised...(x+1)(x+1)=0, so x=-1, so cosT = -1.
Now you need to tell me the range of theta, so you can find the answers.
cosT = 1 is 0 degrees, and -1 is 180 degrees.
cheers
Jon.